Question

if a( 3,5) and b (- 1,7 )are any two points find the distance 3 ab​

Answer 1

Step-by-step explanation:

$ab = \sqrt{ {4}^{2} + { (- 2)}^{2} } \\ = \sqrt{20} \\ = 2 \sqrt{5} \\ 3ab = 6 \sqrt{5}$

MARK AS BRAINLIEST.

Answer 2

Answer:

3ab = 2$\sqrt{20}$

Step-by-step explanation:

In this question we are given that

a(3,5) represents 'a' is at the point where x1 = 3 and y1 = 5

b(-1,7) represents 'b' is at the point where x2 = -1 and y2 = 7

To find 3ab, we may use this formula

$3ab =\sqrt{(x1-x2)^{2} +(y2-y1)^{2}$

Plugging the values, we get

ab = \sqrt{(-1-3)^{2} +(7-5)^{2}[/tex]

ab = $\sqrt{16+4}$

3ab = 3$\sqrt{20}$

This is required distance between point a and point b