Math, asked by gowsiya8861, 8 months ago

If A(-3,5) B(-2,-7) C(1,-8) and D(6,3) are the vertices of a quadrilateral ABCD. Find its area.

Answers

Answered by Kusumaswetha
1

Answer:

72cm^2

Step-by-step explanation:

In triangle ABD,

Area of triangle 

=1/2[-3(-7-3)-2(3-5)+6(5+7)

= 1/2 [-3×-10 -2×-2 +6×12]

=1/2 × 30 +4 +72

=1/2×106

=53cm

in triangle BCD

area of triangle

=1/2 [-2(-8-3)+1(3+7)+6(-7+8)

=1/2[-2×-11 +10+6]

=1/2×22+10+6

=1/2×38

=19 cm

so,area of quadilateral=area of triangle ABD+area of triangle BCD

=53+19 = 72 cm²

I think it helps you a lot

Answered by sailakshmithareddy
0

Answer:

Step-by-step explanation:

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