if a=3+/5 by 2 then find the value of a^2+1 bya^2
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ANSWER IS 7
HOPE THIS HELPS YOU
Step-by-step explanation:
a=(3+_/5)/2
Therefore, 1/a=2/(3+_/5)
=2(3-_/5)/(3+_/5)(3-_/5)
=2(3-_/5)/(9-5)
=2(3-_/5)/4
=(3-_/5)/2
The value of
(a+1/a)={ (3+_/5)/2}+{(3-_/5)/2}
=6/2=3
Now a^2+(1/a^2)=(a+1/a)^2-2(a)(1/a)
=(a+1/a)^2 - 2
=3^2-2
=9-2=7
THE VALUE OF. a^2+(1/a^2)=7
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