if A =[3/5/x 2/5/y] A2=1 find the value of x and y
Answers
Answer:
Find the value of X and Y if
2X+3Y=[
2
4
3
0
] 3X+2Y=[
2
−1
−2
5
]
→ let Assume [
2
4
3
0
] = A
[
2
−1
−2
5
] = B
→2x+3y=A __ (i)
3x+2y=B __ (ii)
→ multiple equation (i) with 2 & equation (ii) with (3)
4x+6y=2A
9x+6y=3B
________________
−5x=2A−3B
∴x=
5
−1
[2A−3B]
∴x=
5
3B
−
5
2A
=
5
3
[
2
−1
−2
5
]−
5
2
[
2
4
3
0
]
=[
6/5
−3/5
−6/5
3
]−[
4/5
8/5
6/5
0
]
=[
6/5
−3/5
−4/5
−8/5
−4/5
3
−6/5
−0
]
∴x=[
1/5
−11/5
−12/5
3
]
→ value of x put in equation (i)
∴[
2/5
−22/5
−24/5
6
]+3y=[
2
4
3
0
]
∴3y=[
2−2/5
4+22/5
3+24/5
0−6
]=[
8/5
42/5
39/5
−6
]
∴y=[
8/15
42/15
39/15
−2
]
solution
Answer:
I HOPE THIS IS CLEAR AND PLEASE FOLLOW ME
Step-by-step explanation:
Distance between two points (x1,y1) and
(x2,y2) can be calculated using the
formula (x2−x1)2+(y2−y1)2
Distance between the points (x,−1) and (3,2)=5
=>(x−3)2+(−1−2)2=5
(x−3)2+9=5
(x−3)2+9=25
(x−3)2=16
x−3=+4 or −4
x=7 or x=−1