Math, asked by kunaldas58, 4 months ago

if A =[3/5/x 2/5/y] A2=1 find the value of x and y​

Answers

Answered by parimeshram040
0

Answer:

Find the value of X and Y if

2X+3Y=[

2

4

3

0

] 3X+2Y=[

2

−1

−2

5

]

→ let Assume [

2

4

3

0

] = A

[

2

−1

−2

5

] = B

→2x+3y=A __ (i)

3x+2y=B __ (ii)

→ multiple equation (i) with 2 & equation (ii) with (3)

4x+6y=2A

9x+6y=3B

________________

−5x=2A−3B

∴x=

5

−1

[2A−3B]

∴x=

5

3B

5

2A

=

5

3

[

2

−1

−2

5

]−

5

2

[

2

4

3

0

]

=[

6/5

−3/5

−6/5

3

]−[

4/5

8/5

6/5

0

]

=[

6/5

−3/5

−4/5

−8/5

−4/5

3

−6/5

−0

]

∴x=[

1/5

−11/5

−12/5

3

]

→ value of x put in equation (i)

∴[

2/5

−22/5

−24/5

6

]+3y=[

2

4

3

0

]

∴3y=[

2−2/5

4+22/5

3+24/5

0−6

]=[

8/5

42/5

39/5

−6

]

∴y=[

8/15

42/15

39/15

−2

]

solution

Answered by poojaguptasiwan94
2

Answer:

I HOPE THIS IS CLEAR AND PLEASE FOLLOW ME

Step-by-step explanation:

Distance between two points (x1,y1) and

(x2,y2) can be calculated using the

formula (x2−x1)2+(y2−y1)2

Distance between the points (x,−1) and (3,2)=5

=>(x−3)2+(−1−2)2=5

(x−3)2+9=5

(x−3)2+9=25

(x−3)2=16 

x−3=+4  or −4

x=7 or x=−1

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