If A = {3, 6, 9, 12, 15, 18}, B = {4, 8, 12, 16, 20}, C = {2, 4, 6, 8, 10, 12} and D = {5, 10, 15, 20, 25}, find:
n(A - C)
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A = {3,6,9,12,15,18}
C = {2,4,6,8,10,12}
A-C = {3,9,15,18}
n(A-C) = number of elements present in (A-C) set = 4
C = {2,4,6,8,10,12}
A-C = {3,9,15,18}
n(A-C) = number of elements present in (A-C) set = 4
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the answer is as follows
(A-C)= 4
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(A-C)= 4
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