if A={3,6,9,12,15} write its set builder form
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Answer:
A = {3n | 1<=n<=5}
Step-by-step explanation:
A={3,6,9,12,15} looks like the multiples of 3 (3n)
for n=1, 3n = 3(1) = 3
for n=2, 3n = 3(2) = 6
.
.
.
for n=5, 3n = 3(5) = 15
n is in the range of [1, 5] or 1<=n<=5
Now, we will try to write set builder form for A,
A = {3n | 1<=n<=5}
Note: | denotes such that
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