Question

if A(3,8) B( 4, - 2) and C( 5, -1) are vertices of triangle ABC.Then its area is brainly

Answer 1

Step-by-step explanation:

Given : A(3,8), B( 4, - 2) and C( 5, -1)

Area of Triangle ABC,

= 1/2[X1(y2-y3)+X2(y3-y1)+x3(y1-y2)]

= 1/2[3{-2-(-1)}+4{-1-8}+5{8-(-2)}]

= 1/2[3(-2+1)+4(-9)+5(8+2)]

= 1/2[3(-1)+4(-9)+5(10)]

= 1/2[-3-36+50]

= 1/2[11]

= 11/2 Sq. unit.

Answer 2

The area of the triangle is 5.5 square units.

Step-by-step explanation:

The vertices of a triangle are A(3,8) B( 4, - 2) and C( 5, -1).

Thus, we have

$x_1=3,y_1=8,x_2=4,y_2=-2,x_3=5,y_3=-1$

Area of a triangle is given by the formula

$A=\frac{1}{2}\left[x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)\right]$

Substituting the known values, we get

$A=\frac{1}{2}\left[3(-2+1)+4(-1-8)+5(8+2)\right]$

On simplifying, we get

$A=\frac{1}{2}\cdot11\\\\A=\frac{11}{2}\\\\A=5.5$

The area of the triangle is 5.5 square units.

#Learn More:

Find the area of the triangle with vertices (0,0),(6,0),(0,5)

https://brainly.in/question/11112110