Question

if a(3 8) b(4 -2) C(5,-1) are the vertices of triangle ABC. Then, its area is

Answer 1

Answer:

Here 

(x1=3 , y1=8);

(x2=−4 , y2=2);

(x3=5 , y3=−1)

Area = (△ABC)=1/2 [ x1(y2−y3) + x2(y3−y1) + x3(y1−y2) ]

=1/2 [3(2+1)−4(1−8)+5(8−2)]

=1/2(9+36+30)

=75/2

=37 1/2

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