if (a^3*a^5)^2=81 find a
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(a^3×a^5)^2=9^2
a^3×a^5=9
a^8=9
a=9^1/8
a^3×a^5=9
a^8=9
a=9^1/8
Answered by
1
(a^3×a^5)^2=81
(a^5+3)^2=81
(a^8)^2=9^2
a^8=9
(a^4)^2=3^2
a^4=3
4=loga3
(a^5+3)^2=81
(a^8)^2=9^2
a^8=9
(a^4)^2=3^2
a^4=3
4=loga3
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