Question

If a = 3 and b = 1, then find the value of 12a−5b−7a−12b+2a+3b.

Answer 1

Answer:

subtract 4a−7ab+3b+12 from 12a−9ab+5b−3

=12a−9ab+5b−3−(4a−7ab+3b+12)

=12a−9ab+5b−3−4a+7ab−3b−12

=8a−2ab+2b−15

it may help you

Answer 2

12a - 5b - 7a - 12b + 2a + 3b

→ (12 × 3) - (5 × 1) - (7 × 3) - (12 × 1) + (2 × 3) + (3 × 1)

→ 36 - 5 - 21 - 12 + 6 + 3

→ 7

Hope it helps