Question

If a=3 and b=-2 find the values of: 1)a^a+b^b 2)a^b+b^a answer:1) 27 1/4 2) -7 8/9 answer only correctly​

Answer 1

Answer:

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Answer 2

Answer:

$\Large{\boxed{\underline{\overline{\mathfrak{\star \: QuEsTiOn :- \: \star}}}}}$

If a=3 and b=-2 find the values of: 1)a^a+b^b 2)a^b+b^a answer:1) 27 1/4 2) -7 8/9

$\huge\underline{\overline{\mid{\bold{\pink{ANSWER-}}\mid}}}$

$the \: value \: of \: a^b \: + \: b^a \: is \: -7 8/9.$

Given :

a = 3

b = -2

To find :

a^a + b^b

$\Large{\underline{\underline{\bf{SoLuTion:-}}}}$

Putting the values of a & b, we get -

$= \: 3³ \: + \: 2-²</p><p></p><p>= \: 27 \: + \: 1/2² \\ </p><p></p><p>= \: 27 \: + \: 1/4 \\ </p><p></p><p>= \: (108 + 1) \: / 4 \\ </p><p></p><p>= \: 109/4 \\ </p><p></p><p>= \: 27 ¼$

Hence, the value of a^a + b^b is 27 ¼.

In the next case,

Given :

a = 3

b = -2

To find :

a^b + b^a

Solution :

Putting the value of a & b, we get -

$= \: 3-² \: + \: (-2)³ \\ </p><p></p><p>= \: 1/3² \: + \: (-8) \\ </p><p></p><p>= \: 1/9 \: \: + \: (-8) \\ </p><p></p><p>= \: 1/9 \: - \: 8 \\ </p><p></p><p>= \: (1 - 72) / 9 \\ </p><p></p><p>= \: -71/9 \\ </p><p></p><p>= \: -7 8/9$

$\mathfrak{\huge{\purple{\underline{\underline{Hence}}}}}$

The value of a^b + b^a is -7 8/9..