Question

if a=3 and b=2 then find the value of (a^a+b^b)^-1

Answer 1

(a^a+b^b)^-1
a=3 and b=2
(3^3+2^2)^-1
(27+4)^-1
31^-1
1/31

Answer 2

Answer:

Given that

a = 2 ; b = 3

(a^b + b^a)^ -1

= (2^3 + 3^2)^ - 1

= (8 + 9)^-1

= (17)^ -1

= 1/17

Thanks