Question

if a =3 and b=-3 find the value of i) a^2+b^2 ii) b^2-a^2 iii) a^2b​

Answer 1

Answer:

i) 0

ii) -18

iii) -27

Step-by-step explanation:

i) a^2+b^2

=3^2+(-3)^2

=9+(-9)

=9-9

=0

ii) b^2-a^2

=(-3)^2-3^2

= -9-9

= -18

iii) a^2b

= 3^2×(-3)

= 9×(-3)

= -27

Answer 2

Answer:

i) a^2+b^2

3^2+(-3^2)

3×3+-3×-3

9+9

18

ii) b^2-a^2

-3^2-(3^2)

-3×-3-(3×3)

+9-(+9)

+9-9

0

iii)a^2b

3^2×-3

3×3×-3

9×-3

-27