Question

if a=3 and b=4,find the value of a³+b³+3ab²+3a²b​

Answer 1

Answer:

3^3+4^3+3*3*4^2+3*3^2*4

= 27 + 64 +144+108

= 343

Answer 2

Answer:

a=3, b=4

a³+b³+3ab²+3a²b..

$a = 3 \\ b = 4 \\ \: \: \: = {a}^{3} + {b}^{3} + 3a {b}^{2} + 3 {a}^{2}b \\ \ \: \: = {3}^{3} + {4}^{3} + 3 \times 3 \times {4}^{2} + 3 \times {3}^{2} \times 4 \\ \: \: \: = 27 + 64 + 9 \times 16 + 3 \times 9 \times 4 \\ \: \: \: =91 + 144 + 108 \\ \: \: \: =235 + 108 \\ \: \: \: =343$

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