Question

If a=3, b=1 and C=-2, find the value of a'+b?+c?+2ab +2bc+2ca

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Answer 1

Answer:

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Answer 2

Answer:

$a + b + c + 2(ab + bc + ca) \\ = 3 + 1 - 2 + 2(3 \times 1 + 1 \times - 2 + 3 \times - 2) \\ = 4 - 2 + 2(3 - 2 - 6) \\ = 2 + 2( - 5) \\ = 2 - 10 = - 8$

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