Question

if a = 3; b= 2/4; c= 1/4, find the value of 2ab-bc/3ac​

Answer 1

$a = 3 \\ b = \frac{2}{4} \\ c = \frac{1}{4} \\ 2ab - \frac{bc}{3ac} = 2 \times 3 \times \frac{2}{4} - \frac{ \frac{2}{4} \times \frac{1}{4} }{3 \times 3 \times \frac{1}{4} } \\ = 3 - \frac{ \frac{1}{8} }{ \frac{9}{4} } = 3 - \frac{1}{18} = \frac{54 - 1}{18} \\ = \frac{53}{18}$