Question

if a=3,b=2 and c=-1 find the value of each of the following expressions.ab+bc+ca+abc​

Answer 1

a=3, b=2, c=-1

$ab = 3 \times 2 = 6$

$bc = 2 \times (- 1 )= - 2$

$abc = 3 \times2 \times ( - 1) = - 6$

$ca = ( - 1) \times 3 = - 3$

ab+bc+ca+abc=6+(-2)+(-6)+(-3)

=6-2-6-3

=6-11

=-5

Answer 2

Here's your answer --

To find : ab + bc + ca + abc

when, a = 3 ,, b = 2 and c = -1

so, ab + bc + ca + abc = ( 3×2 ) + ( 2×-1 ) + ( -1×3 ) + ( 3×2×-1 )

= 6 + ( -2 ) + ( -3 ) + ( -6 ).

= 6 - 2 - 3 - 6

= -2 -3

= -5

so, the answer of the polynomial is -5

now, value of each expression is as follows --

ab = 6

bc = -2

ca = -3

abc = -6

hope it helps !!

have a nice day !!!