Question

if a^3+b^3-1+3ab=0 then find the value of a+b​

Answer 1

Step-by-step explanation:

a+b+x=0 =>a+b= -x Cube on both sides

${(a + b)}^{3} = { - x}^{3} = > {a}^{3} + {b}^{3} +$

$3ab(a + b) + {x}^{3} = 0 = >$

${a}^3 + {b}^3 - 3abx + {x}^{3} = 0$

Compare it with the given equation ,

${a}^{3} + {b}^{3} + 3ab - 1 = 0$

Then we get x= -1 Hence the value of (a+b) is -(-1) =>1. Hope it helps you.