If a^3+b^3 -1+3ab=0 then find the value of a+b
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Answer:
a+b=(root1-3ab)/ab
Step-by-step explanation:
a^3+b^3+3ab-1=0
a^3+b^3+3ab=1
a*b(a^2+b^2+3)=1
a^2+b^2+3=1/a*b
a^2+b^2=1/a*b-3
a^2+b^2=(1-3ab)/ab
(a+b)^2=(1-3ab)/ab
a+b=(root1-3ab)/ab
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