Math, asked by shravya7336, 1 year ago

if a^3+b^3-1+3ab=0 then find the value of a+b​

Answers

Answered by chaitali24
13
Do you mean: 
a^3 + b^3 - 1 + 3ab = 0 
In other words I'm assuming that the question is NOT case sensitive. 
In that case, the left side factors to: 
(a + b - 1)(a^2 - ab + a + b^2 + b + 1) = 0 
So we have two possibilities: 

If a + b - 1 = 0 then a + b = 1 

If a^2 - ab + a + b^2 + b + 1 = 0, that has infinity solutions, but none of them are REAL numbers. 

So if you want to deal with real numbers only, then a + b = 1

shravya7336: thanks a lot
shravya7336: but the book says the answer Is 1
chaitali24: i think now it is right
shravya7336: What's the change ?
chaitali24: see the solution
shravya7336: okay so can I know which identity u have used
Answered by DebayushKarmakar
1

Answer:

1

Step-by-step explanation:

Do you mean:

a^3 + b^3 - 1 + 3ab = 0

In other words I'm assuming that the question is NOT case sensitive.

In that case, the left side factors to:

(a + b - 1)(a^2 - ab + a + b^2 + b + 1) = 0

So we have two possibilities:

If a + b - 1 = 0 then a + b = 1

If a^2 - ab + a + b^2 + b + 1 = 0, that has infinity solutions, but none of them are REAL numbers.

So if you want to deal with real numbers only, then a + b = 1

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