if a^3+b^3-1+3ab=0 then find the value of a+b
Answers
Answered by
13
Do you mean:
a^3 + b^3 - 1 + 3ab = 0
In other words I'm assuming that the question is NOT case sensitive.
In that case, the left side factors to:
(a + b - 1)(a^2 - ab + a + b^2 + b + 1) = 0
So we have two possibilities:
If a + b - 1 = 0 then a + b = 1
If a^2 - ab + a + b^2 + b + 1 = 0, that has infinity solutions, but none of them are REAL numbers.
So if you want to deal with real numbers only, then a + b = 1
a^3 + b^3 - 1 + 3ab = 0
In other words I'm assuming that the question is NOT case sensitive.
In that case, the left side factors to:
(a + b - 1)(a^2 - ab + a + b^2 + b + 1) = 0
So we have two possibilities:
If a + b - 1 = 0 then a + b = 1
If a^2 - ab + a + b^2 + b + 1 = 0, that has infinity solutions, but none of them are REAL numbers.
So if you want to deal with real numbers only, then a + b = 1
shravya7336:
thanks a lot
Answered by
1
Answer:
1
Step-by-step explanation:
Do you mean:
a^3 + b^3 - 1 + 3ab = 0
In other words I'm assuming that the question is NOT case sensitive.
In that case, the left side factors to:
(a + b - 1)(a^2 - ab + a + b^2 + b + 1) = 0
So we have two possibilities:
If a + b - 1 = 0 then a + b = 1
If a^2 - ab + a + b^2 + b + 1 = 0, that has infinity solutions, but none of them are REAL numbers.
So if you want to deal with real numbers only, then a + b = 1
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