Question

if a^3+b^3=200 and a+b=1 then find the value of ab​

Answer 1

Answer:

a^3+b^3=(a+b)^3+3ab(a+b)

>200 =(1)^3+3ab.(1)

>200=1+3ab

>200-1=3ab

>199=3ab

>ab=199÷3

‌>ab=66'334

Answer 2

Step-by-step explanation:

a³+b³ = 200 a+b=1

=a + b³ = 3√200

=

sorry I don't know the after step of yhist