Question

If a^3 - b^3 = 3(a^2)b + 5ab^2, then show that log ((a-b)/2) = 1/3 (log(a) + 2log(b))

Answer 1

Answer:

Mark brainlist

Step-by-step explanation:

(a+b)^2- 2ab=7ab

=>(a+b)^2=9ab

taking square root

=>(a+b)=3(ab)^1/2

taking log

log(a+b)=l0g3+ 1/2(log(ab))

=>l0g(a+b)-log3=1/2[log a+ log b]

=>log[1/3(a+b)]=1/2[log a+ log b]

Hence proved