Question

If a^3 + b^3 + c^3 – 3abc =0 then find the value
of (a^2/bc+b^2/ac-3)​

Answer 1

Step-by-step explanation:

a^2/bc+b^2/ac-3=a^3/abc+b^3/abc-3abc/abc

from given a^3+b3+c^3-3abc=0;

c^3=-(a^3+b^3-3abc)

a^2/bc+b^2/ac-3=a^3+b^3-3abc/abc

=-c^3/abc