Math, asked by amithanup609, 9 months ago

If a^3+b^3+c^3=3abc & a+b+c=0
Prove that
(b+c)^2/3bc + (c+a)^2/3ac + (a+b)^2/3ab = 1

Answers

Answered by adarshraj12371

4

Step-by-step explanation:

I hope you're answers this

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Answered by tiwarivineet64

0

Answer:

Step-by-step explanation:

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