Question

If a^3+b^3+c^3=3abc and a+b+cis not equal to 0 also a-2=0 then

Answer 1

hey mate !!❤✌
here's ur answer ✍✍✍

if a+b+c =0
then
$\bold{{a}^{3} + {b}^{3} + {c}^{3} = 3abc}$
because..
$\bold{{a}^{3} \times {b}^{3} \times {c}^{3} - 3abc} \\ \bold{ =(a + b + c)( {a}^{2} + {b}^{2} + {c}^{2} - ab - bc - ca)}$
$\bold{now \: if \: a + b + c = 0 ......\: so \: {a}^{3 + {b}^{3} + {c}^{3} - 3abc} \: bold{will \: also \: be \: 0 } }$

$\bold{so ....\: {a}^{3} {b}^{3} {c}^{3} - 3abc} \: = 0$

${{a}^{3} \times {b}^{3} \times {c}^{3} = 3abc}$


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