Question

if a^3 +b^3+c^3=3abc,find
bc/(b+c)^2+ca/(c+a)^2+ab/(a+b)^2

Answer 1

Answer:

Step-by-step explanation:

If a^3 +b^3+c^3=3abc, then a+b+c=0

So a+b=-c, a+c=-b and b+c=-a

So LHS=bc/a^2 + ac/b^2 + ab/c^2

=(b^3c^3+a^3c^3+a^3b^3)/(a^2b^2c^2)