Question

if a^3+b^3+c^3=(a+b+c)^3 then find the value of a^5+b^5+c^5-(a+b+c)^5

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Answer 1

Answer:

a³+b³+c³=(a+b+c)³

Step-by-step explanation:

a³+b³+c³=a³+b³+c³+3((a +b) (b + c) (a+ c)

3(a+b)(b+c)(c+a)=0

a+b=0

a=(-b)

NOW

a^5+b^5+c^5-(a+b+c)^5

=>(-b)⁵+b⁵+c⁵-(0+c⁵). (since a=(-b) or a+b=0)

=> b⁵-b⁵+c⁵-c⁵

=0