If a=3, b= -3, find the value of ab2 + a2b + ab
Answers
Given,
a=3
b=-3
Therefore,
= 3×-3×2+3×2×-3+3×-3
= -18+(-18)+(-9)
= -18-18-9
= -27
So, the value of ab2 + a2b + ab is -27.
hope it helps you.
Answer:
(a2 + b2 + c2) ( a + b + c ) = (a - b + c) (a + b + c )2
a3 + ab2 + ac2 + a2b + b3 + c2b + a2c + b2c + c3= ( a - b + c) (a2 + b2 + c2 + 2ab + 2bc + 2ca )
a3 + ab2 + ac2 + a2b + b3 + c2b + a2c + b2c + c3= a3 + ab2 + ac2 + 2a2b + 2abc + 2a2c - a2b - b3- c2b -2ab2 - 2b2c + 2abc + a2c + b2c + c3 + 2abc + 2bc2 + 2c2a
a3 + ab2 + ac2 + a2b + b3 + c2b + a2c + b2c + c3- a3 - ab2 - ac2 - 2a2b - 2abc - 2a2c + a2b + b3 + c2b + 2ab2 + 2b2c + 2abc - a2c - b2c - c3 - 2abc - 2bc2 - 2c2a = 0
a3 + ab2 + ac2 + a2b + b3 + c2b + a2c + b2c + c3- a3 - ab2 - ac2 - 2a2b - 2abc - 2a2c + a2b + b3 + c2b + 2ab2 + 2b2c + 2abc - a2c - b2c - c3 - 2abc - 2bc2 - 2c2a =0 solve this
b( a+ b + c) - ac ( a + b + c) = 0
b = ac
Step-by-step explanation: