Question

If |a|=3,|b|=4 and |a+b|=1, then |a−b|=

Answer 1

Answer:

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We have,

∣a+b∣

2

+∣a−b∣

2

=(a+b)(a+b)+(a−b)(a−b)

=a

2

+2ab+b

2

+a

2

−2ab+b

2

=2∣a∣

2

+2∣b∣

2

Therefore,

∣a+b∣

2

+∣a−b∣

2

5

2

+(a−b)

2

=2(3

2

+4

2

)

25+(a−b)

2

=50

⇒∣a−b∣

2

=25

⇒∣a−b∣=5

Answer 2

Answer:

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