Question

if a /3 =b/4=c/7 ,then a+b+c/c=?

Answer 1

$\frac{a}{3} = \frac{b}{4} = \frac{c}{7}$

$\frac{a}{3} = \frac{c}{7} \\ or, \frac{a}{c} = \frac{3}{7} \\ \\ \frac{b}{4} = \frac{c}{7} \\ or, \frac{b}{c} = \frac{4}{7} \\ \\ \frac{a + b + c}{c} = \frac{a}{c} + \frac{b}{c} + \frac{c}{c} \\ = \frac{a}{c} + \frac{b}{c} + 1 \\ = \frac{3}{7} + \frac{4}{7} + 1 \\ = \frac{3 + 4 + 7}{7} \\ = \frac{14}{7} \\ = 2$

so, the answer is 2.

Answer 2

Answer:

The value of $\frac{a+b+c}{c}$ is 2.

Step-by-step explanation:

It is given that

$\frac{a}{3}=\frac{b}{4}=\frac{c}{7}$

Using this we can say that,

$\frac{a}{3}=\frac{c}{7}$

$\frac{a}{c}=\frac{3}{7}$              .... (1)

$\frac{b}{4}=\frac{c}{7}$

$\frac{b}{c}=\frac{4}{7}$            .... (2)

$\frac{a+b+c}{c}=\frac{a}{c}+\frac{b}{c}+\frac{c}{c}$

Using (1) and (2) we get

$\frac{a+b+c}{c}=\frac{3}{7}+\frac{4}{7}+1$

$\frac{a+b+c}{c}=\frac{3+4}{7}+1$

$\frac{a+b+c}{c}=\frac{7}{7}+1$

$\frac{a+b+c}{c}=1+1=2$

Therefore the value of $\frac{a+b+c}{c}$ is 2.