If a=3,b=-5 and c=6 then find the value of½[(a-b) 2 +(b-c) 2 +(c-a) 2 ]
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The is "0" ..........
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=1/2[(3+5)2+(-5-6)2+(6-3)2]
=1/2[16-22-6]
=1/2[16-28]
=1/2x-12
=-6
=1/2[16-22-6]
=1/2[16-28]
=1/2x-12
=-6
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