Question

If a=3, b=5, c=2 then show that
i.(a+b)² = (a-b)² + 4ab
ii.(a+b)² = a² + 2ab + b²
(please answer this with explanation)

Answer 1

Answer:

64

Step-by-step explanation:

i) (a+b)^2 = (a-b)^2 + 4ab

or, (3+5)^2 = (3-5)^2 + (4×3×5)

or, 8^2 = (-2)^2 + 60

or, (8×8) = [(-2) × (-2)] + 60

or, 64 = 4 +60

or, 64 = 64 (proved)

ii) (a+b)^2 = a^2 + 2ab + b^2

or, (3+5)^2 = 3^2 + (2×3×5) + 5^2

or, 8^2 = (3×3) + 30 + (5×5)

or, (8×8) = 9 + 30 + 25

or, 64 = 64 (proved)

Hope it helps :)