Question

if a=3, b=-5, x=6, y=12, z=-8 then 6y(z+y)+3ab is equal to​

Answer 1

Given,

a=3, b= -5, x=6, y=12, z= -8

6y(z+y)+3ab

To find,

The value of 6y(z+y)+3ab.

Solution,

The value of 6y(z+y)+3ab will be 243.

We can easily solve this problem by following the given steps.

First, we need to put all the given values in the expression, 6y(z+y)+3ab.

a=3, b= -5, x=6, y=12, z= -8

6y(z+y)+3ab = 6 × (12) ( -8+12) + 3 (3)(-5)

Using the BODMAS ( Bracket, Of, Division, Multiplication, Addition and Subtraction) rule, we will first solve the bracket, then multiplication and then addition.

(Note that the multiplication of a negative and a positive integer is always negative.)

6y(z+y)+3ab = 6×12 (4) + 3(3)(-5)

6y(z+y)+3ab = (72 × 4)+ (3 × -15)

6y(z+y)+3ab = 288 - 45

6y(z+y)+3ab = 243

Hence, the value of 6y(z+y)+3ab is 243.

Answer 2

Answer:

If a=3, b=-5, x=6, y=12, z=-8,  then 6y(z + y) + 3ab = 243.

Step-by-step explanation:

Given: a =3, b = -5, x = 6, y = 12 and z = -8

Find the value of 6y(z + y) + 3ab

Put the given value in 6y(z + y)+ 3 a b

6y(z + y) + 3ab

= 6(12) [(-8) + 12] + 3 ( 3) (-5)

= 72[-8+ 12]+ 9 (-5)

= 72 [4] - 45

= 288 - 45

= 243

So, 6y(z + y) + 3ab = 243.