if a=3+b prove a^3-b^3-9ab=27
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Answered by
7
Hey !
⭐ Here is your answer ⭐
____________
Given
a = 3 + b
---> a - b = 3 [ 1 ]
On cubing both sides of [ 1 ]
( a - b)3 = ( 3 )3
a3 - b3 - 3ab ( a - b ) = 27
a3 - b3 - 3ab ( 3 ) = 27 Given [ a - b = 3 ]
a3 - b3 - 9ab = 27
Proved
Hope it helps ☺
⭐ Here is your answer ⭐
____________
Given
a = 3 + b
---> a - b = 3 [ 1 ]
On cubing both sides of [ 1 ]
( a - b)3 = ( 3 )3
a3 - b3 - 3ab ( a - b ) = 27
a3 - b3 - 3ab ( 3 ) = 27 Given [ a - b = 3 ]
a3 - b3 - 9ab = 27
Proved
Hope it helps ☺
Answered by
3
Answer: It will be proven.
Step-by-step explanation:
a= 3+b
a-b=3----------(i)
Now cubing both sides
(a-b)^3=(3)^3
a^3 - b^3 -3ab(a-b) = 27
a^3 - b^3 -3ab(3) = 27
a^3 - b^3 -9ab = 27. Proven
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