If a = 3 Cos 2 ; and b = 3Sin 2 +1; then find a+b
Answers
Answered by
2
Step-by-step explanation:
Given,
32tan
8
θ=2cos
2
α−3cosα...............(i)
3cos2θ=1
This gives
1+tan
2
θ
1−tan
2
θ
=
3
1
So, tan
2
θ=
2
1
Given equation (i) becomes
32(tan
2
α)
4
=2cos
2
α−3cosα
⇒32×
16
1
=2cos
2
α−3cosα
⇒2=2cos
2
α−3cosα
⇒2cos
2
α−3cosα−2=0
⇒2cos
2
α−4cosα+cosα−2=0
⇒2cosα(cosα−2)+1(cosα−2)=0
⇒(2cosα+1)(cosα−2)=0
So, cosα=−
2
1
or cosα=2
∵cosα
=2
∴cosα=−
2
1
⇒α=
3
2π
So. general solution is α=2nπ±
3
2π
Answered by
0
Answer:
If a = 3 Cos 2 ; and b = 3Sin 2 +1; then find a+b
Step-by-step explanation:
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