Question

if a=3 cos square theta; and b=3 sin square theta +1; then find a+b​

Answer 1

Answer:

a=3cos²theta

b= 3sin²theta+1

a+b=-4

Step-by-step explanation:

3cos²theta +3sin²theta+1

●equate to zero and send +1to rhs side

3cos²theta+3sin²theta= -1

●take 3 common and here it becomes identity

3(cos²theta + sin²theta)= -1

3(1)= -1

3= -1

= -1-3

= -4