Question

If a = 3 Cos2θ ; and b = 3Sin2θ +1; then find a+b

Answer 1

Answer:

Analysis→

Here we're given that a =3cos²θ; and b =3Sin²θ+1. And we've to find the value of a+b. And we know that Sin²θ+Cos²θ=1 (1st Trigonometric Identity).

Given→

• a =3Cos²θ
• b=3Sin²θ+1

To Find→

The value of a+b.

Answer→

$\rm\rightarrow{a+b}$

$\rm\rightarrow{(3Cos²θ)+(3Sin²θ+1)}$

$\rm\rightarrow{3(Cos²θ+Sin²θ)+1}$

$\rm\rightarrow{3(1)+1}$

$\rm\rightarrow{3+1}$

$\rm\rightarrow{4}$

${\boxed{\boxed{\rightarrow{\rm{a+b=4✔}}}}}$

☞ Hence the value of a+b(3Cos²θ+3Sin²θ+1) is 4, which is the required answer.

HOPE IT HELPS.

Answer 2

Answer:

♤Analysis→

Here we're given that a =3cos²θ; and b =3Sin²θ+1. And we've to find the value of a+b. And we know that Sin²θ+Cos²θ=1 (1st Trigonometric Identity).

♤Given→

a =3Cos²θ

b=3Sin²θ+1

To Find→

The value of a+b.

♧Answer→

☆→a+b

☆→(3Cos²θ)+(3Sin²θ+1)

☆→3(Cos²θ+Sin²θ)+1

☆3(1)+1

☆→3+1

☆→4

→4→a+b=4✔

✍️☞ Hence the value of a+b(3Cos²θ+3Sin²θ+1) is 4, which is the required answer.

HOPE IT HELPS.✨