If a=3+v8.
find the value
of
a²+1/
![{a}^{2} {a}^{2}](https://tex.z-dn.net/?f=+%7Ba%7D%5E%7B2%7D+)
Q?
Answers
Answered by
1
Answer:
18
Step-by-step explanation:
if a=3+√8
then,
a^2=(3+√8)^2
a^2=9+8
a^2+1=9+8+1
a^2+1=18
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