Question

If A (3, y) is equidistant from points P (8, -3) and Q (7,6) , find the value of y and find the distance AQ.

Answer 1

Answer:

Y=1

AQ=√41

Step-by-step explanation:

Dist.AP=√[(3-8)^2+(y+3)^2]

Dist.AQ=√[(3-7)^2+(y-6)^2]

Dist.(AP=AQ) given..

=> √[25+(y+3)^2]=√[16+(y-6)^2]

squaring both sides.,

25+y^2+9+6y=16+y^2+36-12y

or 18y=18

or y=1.

and Dist AQ=√(16+25)=√41