Question

If A=30 degree and b=60 degree,verify that


sin(A+B)=sinA*cosB+cosA*sinB

cos(A+B)=cosA*cosB-sinA*sinB

Answer 1

Hey..

Here's your answer..

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$\sin(60 + 30) = \sin(30) \times \cos(60) + \cos(30) \times \sin(60) \\ \sin(90) = 1 \div 2 \times 1 \div 2 + \sqrt{3} \div 2 \times \sqrt{3} \div 2 \\ 1 = 1 \div 4 + 3 \div 4 \\ 1 = 1 \\ \\ also \: \cos( 90) = \cos(30) \times \ \cos(60) - \sin(30) \times \sin(60) \\ \cos(90) = \sqrt{3} \div 2 \times 1 \div 2 - 1 \div 2 \times \sqrt{3} \div 2 \\ 0 = 0$
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HOPE IT HELPS

@Rêyaañ11

Answer 2

Answer:

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