if A=30 degree,verify that cos2A=1-tan^2A/1+tan^2A
plz answer to this question frnds
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Answered by
73
A= 30
2A = 60
Cos(60) = 1/2
Tan (30) = 1/(root 3)
ATQ
LHS = Cos (60) = 1/2
RHS = 1-tan^2A/1+tan^2A = (1-1/3)/(1+1/3) =(2/3)/(4/3) = 1/2
LHS=RHS
Hence proved
2A = 60
Cos(60) = 1/2
Tan (30) = 1/(root 3)
ATQ
LHS = Cos (60) = 1/2
RHS = 1-tan^2A/1+tan^2A = (1-1/3)/(1+1/3) =(2/3)/(4/3) = 1/2
LHS=RHS
Hence proved
reshmaroopi:
good ans
thanks
hmm
Answered by
17
Answer:
Hey mate here is ur Ans
Step-by-step explanation:
cos 2(30)
cos 60= 1/2
tan 30=1√3
1-tan^2 A/1+tan^2A
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