if A =30 Sin2A =2tanA /1+tan2A
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Given:-
a= 30
sin2A=2tanA/1+tan2A
Solution:-A tan2a = tan 60 = √3
B tan(30) = 1/√3 2tan(30) = 2/√3
C tan(30) ^2 0.3bar
1-(1/3) 2/3
B/C 3/√3
3/√3 * √3/√3 = √3
Therefore the answer is √3
a= 30
sin2A=2tanA/1+tan2A
Solution:-A tan2a = tan 60 = √3
B tan(30) = 1/√3 2tan(30) = 2/√3
C tan(30) ^2 0.3bar
1-(1/3) 2/3
B/C 3/√3
3/√3 * √3/√3 = √3
Therefore the answer is √3
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