Question

if a=30°,b=60° then verify the following tan(a+b) = tan a + tan b/1-tana tan b​

Answer 1

Answer:

It is given that A = 60˚, B = 30˚. Putting A = 60˚ and B = 30˚ in the given equation, we get

tan (A – B) = (tan A – tan B)/(1 + tan A.tan B)

⇒ tan (60˚ – 30˚) = (tan60˚ – tan 30˚)/(1 + tan 60˚. tan 30˚)

⇒ tan 30˚ = (√3 – 1/√3)/1 + √3 × 1/√3

⇒ 1/√3 = 2√3/2

⇒1/√3 = 1/√3

⇒ L.H.S = R.H.S.

Answer 2

$\huge{your \: \: questions}$

if a=60°,b=30° then verify the following tan(a+b) = tan a + tan b/1-tana tan b

$\huge \red{answer}$

$\Rightarrow L.H.S.=tan(60+30)=tan \Rightarrow \infty;$

$R.H.S.= \frac{tan60+tan 30}{1-tan 30 tan 60} \: ;$

$= \frac{ \sqrt{3} + \frac{1}{ \sqrt{3} } }{1 - ( \sqrt{3}){( \frac{1}{ \sqrt{3} }) } } = \frac{ \sqrt{3} ( \sqrt{3} )( \frac{1}{ \sqrt{3} } )}{1 - 1}$

$\Rightarrow \infty;$

$\therefore\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ { \boxed {\Rightarrow{ \fcolorbox{red}{green}{ L.H.S.=R.H.S}}}}$