If A = 300 , find sin 2 A, tan 2 A.
Answers
Answered by
0
Answer:
Given, A=30
∘
Now, sin2A=2sinAcosA=
1+tan
2
A
2tanA
L.H.S: sin2A=sin60
0
=
2
3
Middle Value : 2sinAcosA=2sin30
0
cos30
0
=2(
2
1
)(
2
3
)=
2
3
R.H.S:
1+tan
2
A
2tanA
=
1+tan
2
30
0
2tan30
0
=
1+(
3
1
)
2
2(
3
1
)
=
3
4
3
2
=
2
3
Thus, L.H.S=M.H.S=R.H.S
Answered by
1
Answer:
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