Question

if A=30°, ( sinA- cosA)²=1-sin2A​

Answer 1

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Answer 2

Answer:

Given that A=30

LHS= ( SinA-CosA)2

= ( Sin30-Cos30)2

= ( 1/2-under root 3/2)2

= 1/4+3/4-under root3/2

= 1- under root 3/2

= 2- under root 3/2

RHs = 1- Sin2A

= 1- Sin2(30)

= 1- Sin 60

= 1- under root 3/2

= 2-under root 3/2

LHS = RHS