if A=30° , then prove tan3A=3tanA-tan^3A/1-3 tan^3A
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Put the value of A.
Tan 3A = 3 tan A - tan ^3 A / 1 - 3 tan ^2 A
1 - 3(tan 30)^2 = 1-3(1/root3)^2
=1-3*1/3
=1-1
=0
As the denominator is 0
The above term is ND which is same as tan 3*30 is tan 90
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