if a=30°. Then show that: sin (60°+a) - sin(60°-a)=sin a
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Answered by
5
= sin ( 60°+30°) - sin (60°- 30°)
= sin 90° - sin 30°
= 1 - 1/2
= 1/2
= sin 30°
= sin a (a = 30°)
= sin 90° - sin 30°
= 1 - 1/2
= 1/2
= sin 30°
= sin a (a = 30°)
Answered by
21
Hey friends!!
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Here is your answer↓
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Q. Show that
=> sin(60°+a)-sin(60°-a) = sin a.......(1).
It is given that:-
=> a=30°.
Putting the value of ‘a’ in the equation (1).
→ sin(60°+30°)-sin(60°-30°) = sin30°.
→ sin90°-sin30°=sin30°.
Putting the value of
=> sin90°=1.
=> sin30°=1/2.
→ 1-1/2=1/2.
→ (2-1)/2=1/2.
→ 1/2=1/2.
Hence, it's proved.
☺☺☺ Hope it is helpful for you ✌✌✌.
-------------------------------------------
Here is your answer↓
-------------------------------------------
Q. Show that
=> sin(60°+a)-sin(60°-a) = sin a.......(1).
It is given that:-
=> a=30°.
Putting the value of ‘a’ in the equation (1).
→ sin(60°+30°)-sin(60°-30°) = sin30°.
→ sin90°-sin30°=sin30°.
Putting the value of
=> sin90°=1.
=> sin30°=1/2.
→ 1-1/2=1/2.
→ (2-1)/2=1/2.
→ 1/2=1/2.
Hence, it's proved.
☺☺☺ Hope it is helpful for you ✌✌✌.
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