Question

if A=30° , verify that sin2A=2tanA/(1+tan^A)​

Answer 1

Step-by-step explanation:

2sin30° = 2tan30°/(1+tan30°)

2•½ = 2•√3/2 /(1+√3/2)

-2 =2√3

√3=-1

Answer 2

Step-by-step explanation:

LHS=sin2A

=sin2(30°)

=sin(60°)

=√3/2

RHS=2tanA/(1+tan^A)

=2tan30/(1+tan30^)

={2×1/√3}/{1+(1/√3)^}

=(2/√3)/(1+1/3)

=(2/√3)/(4/3)

=√3/2

LHS=RHS

hence prooved