Question

if A=30° verify that tan2A=2tanA\1-tan squareA

Answer 1

if A=30degree veryfie that tan2A=2tanA/1-tan*2A This question answer is very simple R. H. S: tan2A/1-tan*2A =2.(30degree)/1- 2.(30degree)*2 =2.(1/root3)/2.(1/root3)*2 =(2/root3)/(2/3) =(2/root3).(3/2) =(3/root3) =(root3 .root3)/root3 =root3 L. H. S: tan2A =2.(30degree) =60degree . : tan(60degree)=root3 . : L. H. S=R.H.S (proved) ( Ans)  

Answer 2

ANSWER:-

A=30°

sin2(30°)=2tan30°/1+tan²30

sin60°=2(1/√3)+(1/√3)²

√3/2=2/√3/1+1/√3

=2/√3/3+1/√3

=2/√3/4/3

=2/√3*3/4

=2/√3*√3*√3*4

ANS:- =√3/2.

R.H.S=L.H.S,HENCE VERIFIED