if a = 30begree ; find cos^2a = 1-tan^2a/1+tan^2a
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Cos^2A=Cos^30 =(√3/2)^2= 3/4
1-tan^2a/1+tan^2a
= 1-(1/√3)^2/1+(1/√3)^2
=2/3//4/3=1/2
it must be cos2a
1-tan^2a/1+tan^2a
= 1-(1/√3)^2/1+(1/√3)^2
=2/3//4/3=1/2
it must be cos2a
sidd47:
as 1+tan^2a = sin^2a
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